Showing posts with label AnalyticGeometry. Show all posts
Showing posts with label AnalyticGeometry. Show all posts

November 27, 2006

And another test finished!

And yet another test accomplished!
Crysta set me to scribe on Thursday/Friday, but there was just a pre-test.

HOWEVER,
Today was the day we had our Analytic Geometry unit test. How do you think you guys did? I'm positive to say I did my best on the whole test, except my mind fell apart on the last two questions :

Anyway,
There isn't much to write for today's class, but I sure hope everyone did well on it, despite the difficulties of the questions.

A few reminders:
1. FLICKR ASSIGNMENT -
In class we discussed the assignments, and the pictures involved with it. According to Mr. K, Flickr will not 'activate' (for lack of a better word) our accounts unless we have a minimum of five (5) pictures. So remember to take four more pictures (not of anyone's faces, thanks), of random things, and upload it into your flickr account.

2. MATH PROJECT #1
Don't procrastinate! Get started on your math project now! Reminder: Due Friday, December 1st, 2006. (Oh wow, DECEMBER ALREADY?!?!?!) You have a choice of working by yourself, or with a partner. No outside help, but from books, the internet, or Mr. K! AND also remember that the minimum and expected mark we should all get is an 88%. Let's make them good!

I hope this is a good scribe for today's class, and helps people in reminders. I choose the next scribe to be ....
" -Zeph "

November 26, 2006

BOB - Analytic Geometry

I found this unit to be quite fun with some challenging points to it too. Like people have mentioned already on their BOB's, I tend to make the smallest errors which really screws things up. I hope I'll be aware of the mistakes I make on the test so that I could correct them. I think I'll need to do more reviewing as well so that I can really get the concept down.

November 21, 2006

Analytic Geometry Review and Reminders ...

Your first project was handed out in class today. It is due next Friday, December 1. You can use any presentation format you like. Mr. Harbeck and I have started collecting a list of free online tools you can use any time you have a project to do. You can find it here.

Don't forget your first flickr assignments are due on Friday. (Take a picture of an "interesting" (to you) number using your cell phone or digital camera. Upload it to flickr. Include a description of why you chose that number and tag it pc30sf06.)

Below is the review sheet we talked about in class today ... try to finish it for class tomorrow. The test is next Monday.

November 15, 2006

Applications with Systems of Linear Equations

Hi it's me ben again. Today in class Mr.K created a new rule to get people to participate in class and that's to pair up and let one person speak for the other person. Okay back to the math. Today we started with some Systems Of Linear Equations With Three Variable questions for practice.

a+2b+c=0
3a-b-2c=11
2a+b-c=3

3a+3b=3
5a+3b=11
2a=8
a=4

3(4)+3b=3
12+3b=3
3b=-9
b=-3

4+2(-3)+c=0
4-6+c=0
-2+c=0
c=2

EXPLANATION:
L1
L2
L3
L4=L1+L3
L5=2L1+L2
L6=L5-L4
L7 Solve L6
L8 Solve L4 w/ a=4
L9 Solve L8
L10 Solve L1 w/ a=4, b=-3
L11 Solve L10

Lines intersect @(4, -3, 2)

After a little work on that question we had to apply our Linear Equation skills we just learned and use them in word problems.

1.When 3 numbers are added in pairs the sums of the pairs are 28, 39, 45. What are the three number?
2Mark sells wildlife photos at the county fair, his revenue, R dollars is determined by the price, p dollars, that he charges for each picture as shown in the equation:
R(p)=ap²+bp+c
At a price of $40, his revenue is $2900
At a price of $50, his revenue is $3000
At a price of $70, his revenue is only $2600
Find the values of a,b, and c

Okay for #1 we need to find out the equation. So it states that the numbers are add in pairs so we need the possible combinations for the 3 equations and they are shown below then now solve.
a+b=28
a+c=39
b+c=45

-b+c=17
2c=62
c=31

b+31=45
b=14

a+31=39
a=8

EXPLANATION:
L1
L2
L3
L4=L2-L1
L5+L4
L6 Solve L5
L7 Solve L3 w/ c=31
L8 Solve L2 w/ c+31

Numbers are 8, 14, 31

For #2 we need to get another equation for each price and revenue. Notice that the price is p so just sub the price of each set of pictures and same with the revenues and you should get this:
a(40)²+40b+c=2900
a(50)²+50b+c=3000
a(70)²+70b+c=2600

Now just simplify and Solve
1600a+40b+c=2900
2500a+50b+c=3000
4900a+70b+c=2600

2400a+20b=-400
900a+10b=100
600a=-600
a=-1

900(-1)+10b=100
-900+10b=100
10b=1000
b=100

-1600+4000+c=2900
4000+c=4500
c=500

EXPLANATION:
L1
L2
L3
L4=L3-2
L5=L2-L1
L6=L4-2L5
L7 Solve L6
L8 Solve L5 w/ a=-1
L9 Solve L1 w/ a=-1, b=100

Therefore a=-1, b=100, and c=500

That's what we did today on Applications with Systems of Linear Equations and homework for tonight is EXERCISE #27 *But don't do #'s 1-5*
The next scribe will be M@RK and good night.

November 13, 2006

Systems of Linear Equations in Two Variables

Ok, today in class we did something like the Friday's class. We practiced doing the different techniques on how to solve systems of linear equations in two variables.

We were given three systems to solve:

x=y+6
3x-5y=7

3x+2y=16
y+7x=19

2x+3y=4
5x+2y=3

Ok, lets do the first one. This first question is best suited to be answered using the substitution technique, because as you can see there is a equivalent for the x value.

x=y+6
3x-5y=7
3(y+6)-5y=7
3y+18y-5y=7
-2y=-11
y=11/2
x=11/2+6
x=11/2+12/2
x=23/2

Therefore, these lines intersect at (23/2,11/2).

Now, lets do the second one.This certain question is best suited to be answered using the elimination technique , because there is no equivalent on any of the variables unlike the first one.

3x+2y=16
y+7x=19

3x+2y=16
7x+y=19
-11x=-22
x=2
7(2)+y=19
y=5

Therefore,these lines intersect at (2,5).

Lastly, before we do some word questions. This question is suited to be answered using the elimination technique just like the second one.

2x+3y=4
5x+2y=3
-11x=-1
x=1/11
3y=4-2x
3y=44/11-2/11
3y=42/11
y=14/11

Here we go again with this word questions....

125 tickets were sold at a basketball game. A total of $337.50 was collected. Students paid $2.50/ticket and other people paid $3.50. How many students attended the game?

Let s=# of student's tickets
p=#of other people's tickets

2.50s+3.50p=337.50
s + p =125
-s =-100
s=100

Therefore , there are 100 student tickets and 25 other people's tickets.

After doing all the warm up things Mr. K started talking about consistent and inconsistent lines.
A consistent line means that there is an answer.It can be break up into a dependant and an independant line. Independant means that there is only one solution. Dependant means that there is an infinite amount of solutions. An inconsistent line means that there is no solution.

I'll be editing this tomorrow because the html codes for line 1 and line 2 doesn't seem to work.

The scribe for tomorrow is ............... "SAMUS" .

Sorry SAMUS ,but you're the one that pop into my hEAD first. I was gonna pick Lauressa but she said her computer wasn't working...

Homework for tonight is Exercise 25 excluding questions number 1 and 2.

November 02, 2006

FIRST SCRIBE FOR NOVEMBER

Today in class we got to look at mr.k's mac. He believes that Firefox is better than Explorer


Our homework is to make an account on del.icio.us and find 1 site for each unit we have studied so far using Firefox. del.icio.us allows you to save bookmarks which you are able to access from any computer no matter where you are.


This is how to do it:
- Open up firefox
- Type del.icio.us in the address box
- Click register
- Click install extension now
- Restart Firefox
- Go to help and click bookmarklet buttons for any browser
- Drag the post to del.icio.us button to where your tabs (beside latest headlines)
- Find 1 site for each unit that we have done so far
- To bookmark a site, click the tag button on your toolbar and save it
- Find a site for each unit we studied and bookmark it with pc30sf06 as one of the tags


Another thing to check out is http://k12onlineconference.org and go to Basic/Advanced Thinking scroll down to the second last post which is posted byAlan Levine. This shows you different education tools and how to use them.




We also started a new unit today called Analytic Geometry we started off with a diagram:

From this diagram you can pull out this information:
OP = r


You can change the distance formula which is (x-h)
2 + (y-k)2
= r into standard form.
Standard form for the equation of a cirlcle is (x-h)2 +
(y-k)2 = r2


If the coordinates for the center point of the circle was (2,color=blue>-1) the formula would be:
(x-2)2 + (y-(-)1)
2 = 9 and the radius would equal the square root of 9
which is 3

The graph for this formula would look like this:





So if you know (h,k) and the center point of a circle, you can write the equation of the circle.

Eg. If the coordinates of the center point is (-3,4) and the radius is 5 this is what you do:
substitute them in: (x+3)2 + (y-4)2 = 25 ** be careful with the signs
then you expand: x2-4x+4+y2+2y+1= 5
after that, simplify: x2+y2-4x+2y+1=0 which is the general
form
when you finish simplifying, complete the square: x2-4x+4+y2+2y+1=0+4+1
(x-2)2+(y+1)2 = 5 and this becomes the original
equation



* you get +4 by taking half of -4 from "-4x" which is -2 and squaring it +1 by taking half of the 2 from "2y" and squaring it.


[ ! ] If you are ever given the diameter, remember that the radius is half of the diameter




Homework is not only creating an account for del.icio.us, Exercise 21 is also for homework OH.. AND THE SCRIBE FOR TOMORROW IS eeDce :)