So yes, its me EEDCE.

**(1) In the diagram below, AB and CB are tangents to a circle with radius 10. If angle AB**

*find x*, the shortest distance from B to the circle.cos50°=10/h

h = 10/cos50

h = 15.557units

x = h - 10

x = 15.557 - 10**x = 5.557 units**

**(2) Given: Circle with centre C**

- Angle 1 = Angle 2

- Angle 1 = Angle 2

*Prove AB=CD***statement proof**

Angle 1 = Angle B given

BC ~= CD ~= AC radii

Triangle ABC is isoscles from above

Triangle ACD is isoscles from above*Therefore, AB cannot be congruent to CD.***8.** *Complete the proof:***Diagram clarification: E, D, C are collinearGiven: EA is tangent to the circle at A**

**AB EC**

**AD // BC given**

*Statement Proof*

EA is tangent at A given

Angle 8 = Angle 7 Tangent-Chord Theorem

Angle 7 = Angle 5 Alternate Angles

Angle 6 = Angle 8 - Angle 9 Tangent-Chord Theorem

Angle 1 = Angle 2 Triangle ABC ~ Triangle AEC

Okay. thats it folks.

homework is to finish the rest of this pre-test if not yet done so.

SANDY will take it away tomorrow.

good job (bet you spent time on it;)

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