*Okay. So lets get this scribe going.*

**Well well well. Another friday scibe post!**Minutes after the 5th period bell, we all walk into our Pre-Cal class, as we do everyday and by our dismay we spot

**Mr. K holding a small stalk of papers**. Since we're all "

*smarter then the average bear*", we immediately knew a lovely

**quiz**was coming in our direction. So after a brief discussion of wither or not we should include quizes for marks, we all got to work. The quiz was nothing new; a nicely summed up quiz about everything we learned so far in

*.*

**'Analytic Geomtry'****After self marking our peer's quizes, Mr. K placed the following questions on the board.**

**S O L V E**

**:**

Question 1:

Question 1:

**x²+x<6**

Okay, so we haven't seen much of these before and you may be a little puzzled.

**BUT**- think back to the

*Mathmatician who set the house on fire*

*"*

**Turn the problem into something we already know how to solve**"First and foremost-

**Ignore the "<" for now**, think of

**it as an "="**

**x²+x=6**

And if we

**move the 6**to the opposite side..

**x²+x-6=0**

Why what do we have here?

**A parabola!**

*Not too terrifying is it?*

Okay so lets

**place the "<" back**.

**x²+x-6<0**

Before actually solving this equation, it would help to

*understand what infact the question is asking*. Well what we're trying to do is-

"

**Find the values of X where this parabola will have negative values**"

So first we must

**factor**the equation we came up with

**x²+x-6<0**

**(x+3)(x-2)<0**

Once we get the two roots,

**you must draw the line graph**(it will be included for marks for the final answer). Finally pick any point in each of the

**3 regions**and sub it into the equation.

**Answer: (-3, 2)**

Remember! we use round brackets **"( )"** because we know the -3 and 2 are *not included* because the original **equation did not include "≤"** (less then AND equals to)

**Question 2:**

**2x-3=5**

Remember! The values in the absolute signs

**"x"**can be both

*negative*and

*positive*, leaving us with

**two cases.****Case #1**2x-3=-5

2x=-2

**x=-1**

**check:**

*it works!*

**Case #2**

2x-3=5

2x=8

**x=4**

**check:**

*it works!*

Okay that was simple enough, BUT- *what if we had..***2x-2>5**

Yikes! Do not fear, remember- **ignore the "<"** and **treat it as an "="** *for now*.

So we'd continue to solve just like before-**Case #1**

2x-3>5

2x>8**x>4****Case #2**2x-3>-5

2x>-2

**x>-1**

**Answer: ****(-∞,1)U(4,∞)**

**"U" - Union**, that group

*together*with this group

**To be finished soon, very soon.Sorry folks!**

**Homework assignment:** All the questions you didn't get done on the past exercises (up to Exercise 28).*Mondays scribe will be Mel!isa*

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*Enjoy your weekend!*
edcee, I was just wondering , who's the scribe?and I forgot the homework coz I remember Mr. K saying about the review thing at the booklet.

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